According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the…
According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon?
$n=6$ to $n=1$
$n=5$ to $n=4$
$n=6$ to $n=5$
$n=5$ to $n=3$
Solution
$\because \Delta E \propto\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$, where $n_2 > n_1$ Energy of photon obtained from the transition $n=6$ to $n=5$ will have least energy.