According to Raoult's law mole fraction of solute in solution is given by formula

According to Raoult's law mole fraction of solute in solution is given by formula
  1. $\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}$
  2. $\frac{\mathrm{P}_1^0}{\mathrm{P}_1}$
  3. $\frac{\mathrm{P}_1^0}{\Delta \mathrm{P}}$
  4. $\frac{\mathrm{P}_1}{\mathrm{P}_1^0}$

Solution

$P_1=$ Vapour pressure of solution $\mathrm{P}_1^0=$ Vapour pressure of pure solvent Mole fraction of solute $=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}$

Asked in: MHT CET 2021 (24 Sep Shift 2)

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