According to Newton's law of cooling, the rate of cooling of a body is proportional to $(\Delta heta)^{\mathrm{n}}$, where $\Delta heta$ is the difference of the temperature of the body and the surroundings, and $n$ is equal to

Question

According to Newton's law of cooling, the rate of cooling of a body is proportional to $(\Delta 	heta)^{\mathrm{n}}$, where $\Delta 	heta$ is the difference of the temperature of the body and the surroundings, and $n$ is equal to

Aicharya · Accepted Answer

$\frac{\mathrm{dH}}{\mathrm{dt}} \propto\left(	heta_2-	heta_1ight)=(\Delta 	heta)^{\mathrm{n}} \Rightarrow \mathrm{n}=1$

According to Newton's law of cooling, the rate of cooling of a body is proportional to $(\Delta…

Solution