According to "molecular orbital theory", which among the following diatomic molecules only has $\pi$-bonds?

According to "molecular orbital theory", which among the following diatomic molecules only has $\pi$-bonds?
  1. $\mathrm{N}_2$
  2. $\mathrm{H}_2$
  3. $\mathrm{C}_2$
  4. $\mathrm{Be}_2$

Solution

Molecular orbital configuration of $\mathrm{C}_2$ is $\sigma l s^2 \sigma * 1 s^2 \sigma 2 s^2 \sigma * 2 s^2 \pi 2 p_x^2=\pi 2 p_y^2$ So, $\mathrm{C}_2$ molecule contains only $\pi$-bonds.

Asked in: AP EAMCET 2021 (24 Aug Shift 2)

Practice more Chemical Bonding and Molecular Structure questions on Aicharya