According to "molecular orbital theory", which among the following diatomic molecules only has $\pi$-bonds?
According to "molecular orbital theory", which among the following diatomic molecules only has $\pi$-bonds?
- $\mathrm{N}_2$
- $\mathrm{H}_2$
- $\mathrm{C}_2$
- $\mathrm{Be}_2$
Solution
Molecular orbital configuration of $\mathrm{C}_2$ is
$\sigma l s^2 \sigma * 1 s^2 \sigma 2 s^2 \sigma * 2 s^2 \pi 2 p_x^2=\pi 2 p_y^2$
So, $\mathrm{C}_2$ molecule contains only $\pi$-bonds.
Asked in: AP EAMCET 2021 (24 Aug Shift 2)
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