According to molecular orbital theory, the total number of bonding electron pairs in $\mathrm{O}_2$ is

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Aicharya · Accepted Answer

The molecular orbital electronic configuration of $\mathrm{O}_2$ is $\begin{aligned} & \mathrm{O}_2\left(8+8=16 e^{-}ight)=\sigma 1 s^2, \sigma 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \ & \sigma 2 p_z^2, \pi 2 p_x^2, \approx \pi 2 p_y^2, \stackrel{*}{\pi} 2 p_x^1 \approx \stackrel{*}{\pi} 2 p_y^1 \ & \end{aligned}$ (Unstarred $\sigma$ and $\pi$ represent bonding orbitals.) $	herefore$ number of bonding electrons $=10$ and number of bonding electron pairs $=5$

According to molecular orbital theory, the total number of bonding electron pairs in $\mathrm{O}_2$ is

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