According to Gauss law of electrostatics, electric flux through a closed surface depends on
According to Gauss law of electrostatics, electric flux through a closed surface depends on
The shape of the surface
The volume enclosed by the surface
The area of the surface
The quantity of charges enclosed by the surface
Solution
According to Gauss' law
$\phi=\oint \vec{E} \cdot d \vec{s}=\frac{q_{\text {enclosed }}}{\varepsilon_0}$
$\therefore \quad$ Flux depends on quantity of charges enclosed by surface.
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