According to Bohr's theory, the moment of momentum of an electron revolving in $4^{\text {th }}$ orbit of…

According to Bohr's theory, the moment of momentum of an electron revolving in $4^{\text {th }}$ orbit of hydrogen atom is:
  1. $\frac{h}{\pi}$
  2. $\frac{h}{2 \pi}$
  3. $8 \frac{h}{\pi}$
  4. $2 \frac{h}{\pi}$

Solution

Moment of momentum is $\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{P}}$ $\begin{aligned} & \overrightarrow{\mathrm{L}}=\overrightarrow{\mathrm{r}} \times \mathrm{m} \overrightarrow{\mathrm{v}} \\ & \mathrm{L}=\mathrm{mvr}=\frac{\mathrm{nh}}{2 \pi}=\frac{4 \mathrm{~h}}{2 \pi}=\frac{2 \mathrm{~h}}{\pi} \end{aligned}$

Asked in: JEE Main 2024 (04 Apr Shift 2)

Practice more Structure of Atoms and Nuclei questions on Aicharya