According to Bohr's theory of hydrogen atom, the total energy of the electron in the $n^{\text {th }}$…
According to Bohr's theory of hydrogen atom, the total energy of the electron in the $n^{\text {th }}$ stationary orbit is
directly proportional to $\mathrm{n}$
inversely proportional to $\mathrm{n}$
directly proportional to $\mathrm{n}^2$
inversely proportional to $\mathrm{n}^2$
Solution
According to Bohr's theory of hydrogen atom, the equation for total energy of the electron in the $\mathrm{n}^{\mathrm{th}}$ stationary orbit is,
$\begin{aligned}
& \mathrm{E}_{\mathrm{n}}=\frac{-\mathrm{mZ}^2 \mathrm{e}^4}{8 \varepsilon_0{ }^2 \mathrm{~h}^2 \mathrm{n}^2} \\
\therefore \quad & \mathrm{E}_{\mathrm{n}} \propto \frac{1}{\mathrm{n}^2}
\end{aligned}$
^