A + 2 B → C , the rate equation for the reaction is given as Rate = k [ A ] [ B ] If the concentration…

A+2BC , the rate equation for the reaction is given as

Rate =k[A][B]

If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself?
  1. Doubled
  2. Halved
  3. The same
  4. Quadrupled

Solution

The order of the overall reaction is 2.

 Rate =k[A][B]=R

R'=k[A][2B]

RR'=k[A][B]k[A][2B]=k[A][B]2k[A][B]

2R=R' i.e, rate become doubles.

Asked in: JEE Main 2015 (11 Apr Online)

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