A Zener of breakdown voltage V Z = 8   V and maximum Zener current, I ZM = 10   mA is subjected to…

A Zener of breakdown voltage VZ=8 V and maximum Zener current, IZM=10 mA is subjected to an input voltage Vi=10 V with series resistance R=100 Ω. In the given circuit RL represents the variable load resistance. The ratio of maximum and minimum value of RL is _____ .

Solution

Minimum value of RL for which the diode is shorted is 

RLRL+100×10=8RL=400 Ω

For maximum value of RL, current through diode is 10 mA

So, iR=iRL+IZM

2100=8RL+10×10-310×10-3=8RLRL=800 Ω

So, RLmaxRLmin=2

Asked in: JEE Main 2022 (28 Jun Shift 2)

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