A Young's double slit interference arrangement with slits S 1 and S 2 is immersed in water (refractive index…

A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index =43 ) as shown in the figure. The positions of maxima on the surface of water are given by x2=p2m2λ2-d2 , where λ is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer. The value of p is

Solution



x1=x2+d2
x2=43x2+d2
x=43-1x2+d2=nλ
13x2+d2=nλ
x2+d2=9n2λ2
P=3

Asked in: JEE Advanced 2015 (Paper 1)

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