A wire of resistance $20 \Omega$ is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is _____ $\Omega$.

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Aicharya · Accepted Answer

Each part has resistance $=2 \Omega$ 2 parts are connected in parallel so, $\mathrm{R}=1 \Omega$ Now, there will be 5 parts each of resistance $1 \Omega$, they are connected in series. $\mathrm{R}_{\mathrm{eq}}=5 \mathrm{R}, \mathrm{R}_{\mathrm{eq}}=5 \Omega$

A wire of resistance $20 \Omega$ is divided into 10 equal parts, resulting pairs. A combination of two parts…

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