A wire of resistance $12 \Omega \mathrm{m}^{-1}$ is bent to form a complete circle of radius $10 \mathrm{~cm}$. The resistance between its two diametrically opposite points, $A$ and $B$ as shown in the figure, is

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Aicharya · Accepted Answer

. Circumference of circle $=2 	imes \pi \frac{10}{100}=\frac{2 \pi}{10}=\frac{\pi}{5}$ Resistance of wire $=12 	imes \frac{\pi}{5}=\frac{12 \pi}{5}$ Resistance of each section $=\frac{12 \pi}{10} \Omega$ $	herefore$ Equivalent resistance $=\frac{\frac{12 \pi}{10} 	imes \frac{12 \pi}{10}}{\frac{12 \pi}{10}+\frac{12 \pi}{10}}=\frac{6 \pi}{10}=0.6 \pi \Omega$

A wire of resistance $12 \Omega \mathrm{m}^{-1}$ is bent to form a complete circle of radius $10…

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