A wire of length L m carrying a current I   A is bent in the form of a circle. Magnitude of its…

A wire of length

L

m

carrying a current

I A

is bent in the form of a circle. Magnitude of its magnetic moment is

$\frac{L^{2} I^{2}}{4 π}$
$\frac{L^{2} I}{4 π}$
$\frac{L I}{4 π}$
$\frac{L I^{2}}{4 π}$

Solution

The magnetic moment of a current loop can be defined as the product of the current flowing in the loop and the area of the circular loop, $M = I A$

When a wire is bent to form a circular loop then its area is $A = π {(\frac{L}{2 π})}^{2}$

Therefore, magnitude of its magnetic moment is $M = \frac{L^{2} I}{4 π}$

Asked in: AP EAMCET 2021 (20 Aug Shift 1)

Practice more Magnetic Effects of Current questions on Aicharya