A wire of length ' $L$ ' and linear density ' $m$ ' is stretched between two rigid supports with tension ' $T$ '. It is observed that wire resonates in the $\mathrm{P}^{\mathrm{th}}$ harmonic at a frequency of 320 Hz and resonates again at next higher frequency of 400 Hz . The value of ' $p$ ' is

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Aicharya · Accepted Answer

$\begin{aligned} & 320=\frac{\mathrm{p}}{2 l} \sqrt{\frac{\mathrm{~F}}{\mu}} 	ext { and } 400=\frac{\mathrm{p}+1}{2 l} \sqrt{\frac{\mathrm{~F}}{\mu}} \ & \frac{400}{320}=\frac{\mathrm{p}+1}{\mathrm{p}} \Rightarrow 400 \mathrm{p}=320 \mathrm{p}+320 \ & \mathrm{p}=4\end{aligned}$

A wire of length ' $L$ ' and linear density ' $m$ ' is stretched between two rigid supports with tension '…

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