A wire of $20 \Omega$ is immersed in ice. If $10 \mathrm{~A}$ current is passed through this wire for 1…
A wire of $20 \Omega$ is immersed in ice. If $10 \mathrm{~A}$ current is passed through this wire for 1 minute, ice completely melts. The mass of the ice is nearly $\left(L_{\text {ice }}=79.7 \mathrm{calg}^{-1}\right)$
3.5 g
359 g
540 g
3.5 kg
Solution
$\begin{aligned} \text { Heat gained } & =\text { Heat generated } \\ m L & =I^2 R t \\ \Rightarrow \quad m & =\frac{I^2 R t}{L} \\ & =\frac{100 \times 20 \times 60}{79.7 \times 4.2} \quad(\because 1 \mathrm{cal}=4.2 \mathrm{~J}) \\ & =359 \mathrm{~g}\end{aligned}$