A wire of a certain material is stretched slowly by ten percent. New resistance and specific resistance…
A wire of a certain material is stretched slowly by ten percent. New resistance and specific resistance become respectively
- 1.1 times, 1.1 times
- 1.2 times, 1.1 times
- 1.21 times, same
- Both remain the same
Solution
$\begin{aligned}
& \frac{R_2}{R_1}=\left(\frac{l_2}{l_1}\right)^2=\left(\frac{1.1 l_1}{l_1}\right)^2=1.21 \\
& R_2=1.21 R
\end{aligned}$
Asked in: NEET 2008 (Mains)
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