A whistle emitting a sound of frequency $440\text{ Hz}$ is tied to a string of $1.5\text{ m}$ length and…
A whistle emitting a sound of frequency $440\text{ Hz}$ is tied to a string of $1.5\text{ m}$ length and rotated with an angular velocity of $20\text{ rad s}^{-1}$ in the horizontal plane. Then the range of frequencies heard by an observer stationed at a large distance from the whistle will be ($v = 330\text{ ms}^{-1}$)
400.0 Hz to 484.0 Hz
403.3 Hz to 480.0 Hz
400.0 Hz to 480.0 Hz
403.3 Hz to 484.0 Hz
Solution
Velocity of source (or whistle), $v_s = R \omega = 30\text{ ms}^{-1}$
Maximum frequency will be heard when whistle is at $P$ and minimum at $Q$.
[The diagram shows a circular path of the whistle with point $P$ at the bottom, point $Q$ at the top, and observer $O$ on the horizontal line from the center]
At $P : f_{\max} = f \left( \frac{v}{v - v_s} \right) = 440 \left( \frac{330}{330 - 30} \right) = 484\text{ Hz}$ and
At $Q : f_{\min} = f \left( \frac{v}{v + v_s} \right) = 440 \left( \frac{330}{330 + 30} \right) = 403.3\text{ Hz}$