A wheel of angular speed $600 \mathrm{rev} / \mathrm{min}$ is made to slow down at a rate of $2 \mathrm{rad} \mathrm{s}^{-2}$. The number of revolutions made by the wheel before coming to rest is

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Aicharya · Accepted Answer

$\mathrm{w}_0=600 \mathrm{rev} / \mathrm{min}=\frac{600 	imes 2 \pi}{60}=20 \pi \mathrm{rad} / \mathrm{s}$ $\alpha=-2 \mathrm{rad} / \mathrm{s}^2, \omega=0$ using, $\omega^2=\omega_0^2+2 \alpha 	heta$ $\begin{aligned} & \Rightarrow \quad 0=(20 \pi)^2-2 	imes 2 	imes 	heta \ & 	herefore \quad 	heta=100 \pi^2\end{aligned}$ $	herefore \quad$ Number of revolutions $=\frac{	heta}{2 \pi}=\frac{100 \pi^2}{2 \pi}=157$

A wheel of angular speed $600 \mathrm{rev} / \mathrm{min}$ is made to slow down at a rate of $2 \mathrm{rad}…

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