A wheel has angular acceleration of 3.0 $\mathrm{rad} / \mathrm{sec}^2$ and an initial angular speed of $2~ \mathrm{rad}/ \mathrm{sec}$. In a time of $2 \mathrm{sec}$ it has rotated through an angle (in radian) of:

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Aicharya · Accepted Answer

Here $	heta=\omega t+\frac{1}{2} t^2$ $\begin{aligned} & =(2)(2)+\frac{1}{2}(3)(2)^2 \ & =4+6=10 \mathrm{rad} \end{aligned}$

A wheel has angular acceleration of 3.0 $\mathrm{rad} / \mathrm{sec}^2$ and an initial angular speed of $2~…

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