A wave of frequency $400\text{ Hz}$ has a wave velocity of $300\text{ ms}^{-1}$. The phase difference…

A wave of frequency $400\text{ Hz}$ has a wave velocity of $300\text{ ms}^{-1}$. The phase difference between two displacements at a certain point at time $t = 10^{-3}\text{ s}$ apart is
  1. $72^\circ$
  2. $102^\circ$
  3. $180^\circ$
  4. $144^\circ$

Solution

Phase difference, $\Delta \phi = \left(\frac{2\pi}{T}\right) (\Delta t) = \left(\frac{2\pi}{1/400}\right) (10^{-3}) = 0.8 \pi = 144^\circ$

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