A wave of amplitude $A = 0.2 ext{ m}$, velocity $v = 360 ext{ ms}^{-1}$ and wavelength $60 ext{ m}$ is travelling along positive $X$-axis, then the correct expression for the wave is

Question

A wave of amplitude $A = 0.2	ext{ m}$, velocity $v = 360	ext{ ms}^{-1}$ and wavelength $60	ext{ m}$ is travelling along positive $X$-axis, then the correct expression for the wave is

Aicharya · Accepted Answer

$k = \frac{2\pi}{\lambda} = \frac{2\pi}{60}$ and $\omega = vk = (360)\left(\frac{2\pi}{60}ight) = 12\pi$ $	herefore y = 0.2 \sin 2\pi\left(6t - \frac{x}{60}ight)$

A wave of amplitude $A = 0.2\text{ m}$, velocity $v = 360\text{ ms}^{-1}$ and wavelength $60\text{ m}$ is…

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