A very small hole in an electric furnace is used for heating metals. The hole nearly acts as a black body.…

A very small hole in an electric furnace is used for heating metals. The hole nearly acts as a black body. The area of the hole is $200 \mathrm{~mm}^2$. To keep a metal at $727^{\circ} \mathrm{C}$, heat energy flowing through this hole per sec, in joules is $\left(\sigma=5.67 \times 10^{-8} \mathrm{Wm}^{-2} \mathrm{~K}^{-4}\right)$
  1. $22.68$
  2. $2.268$
  3. $1.134$
  4. $11.34$

Solution

By Stefan's law If the absolute temperature of a black body is $T$, then the energy $E$ emitted per second per unit surface area of the body $ \begin{aligned} & E \propto T^4 \\ & E=\sigma \cdot A T^4 \end{aligned} $ Given, $ \begin{aligned} \sigma & =5.67 \times 10^{-8} \mathrm{~W} / \mathrm{m}^2 \mathrm{~K}^4 \\ T & =727+273=1000 \mathrm{~K} \\ A & =200 \times 10^{-6} \mathrm{~m} \\ E & =5.67 \times 10^{-8} \times\left(200 \times 10^{-6}\right) \times(1000)^4 \\ & =5.67 \times 2 \times 10^{-12} \times 10^{12} \\ & =11.34 \mathrm{~J} / \mathrm{s} \end{aligned} $

Asked in: AP EAMCET 2014

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