A variable line passing through a fixed point $(\alpha, \beta)$ intersects the coordinate axes at $A$ and…

A variable line passing through a fixed point $(\alpha, \beta)$ intersects the coordinate axes at $A$ and $B$. If $O$ is the origin, then the locus of the centroid of the $\triangle O A B$ is
  1. $\beta x+\alpha y-2 \alpha \beta=0$
  2. $\beta x+\alpha y-3 x y=0$
  3. $\alpha x+\beta y-\left(\alpha^2+\beta^2\right)=0$
  4. $\beta x+c y+3 x y=0$

Solution

Let points $A(a, 0)$ and $B(0, b)$, so equation of variable line is $ \frac{x}{a}+\frac{y}{b}=1 $ Since the variable line (i) passes through the point $(\alpha, \beta)$ So, $ \frac{\alpha}{a}+\frac{\beta}{b}=1 $ Now, centroid of $\triangle O A B$ is $\left(\frac{a}{3}, \frac{b}{3}\right)=(h, k)$ So, $ a=3 h \text { and } b=3 k $ From Eqs. (ii) and (iii), we are getting $ \frac{\alpha}{3 h}+\frac{\beta}{3 k}=1 $ On taking locus of point $(h, k)$, we are getting $ \beta x+\alpha y-3 x y=0 . $

Asked in: AP EAMCET 2018 (23 Apr Shift 2)

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