A unit charge moves on an equipotential surface from a point $A$ to point $B$, then

A unit charge moves on an equipotential surface from a point $A$ to point $B$, then
  1. $\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=+\mathrm{ve}$
  2. $\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=0$
  3. $\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-\mathrm{ve}$
  4. it is stationary

Solution

Potential should be same i.e. $\mathrm{V}_{\mathrm{A}}=\mathrm{V}_{\mathrm{B}}$ /

Asked in: JEE Mains - Electrostatics - Test 3

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