A uniformly charged conducting sphere of $4.4$ $\mathrm{m}$ diameter has a surface charge density of 60 $\mu…
- $7.3 \times 10^{-3} C$
- $3.7 \times 10^{-6} \mathrm{C}$
- $7.3 \times 10^{-6} C$
- $3.7 \times 10^{-3} C$
Solution
$\sigma=60 \mu \mathrm{C} m^{-2}$
Charge on the sphere, $q=\sigma \times 4 \pi r^{2}$ $=60 \times 10^{-6} \times 4 \times \frac{22}{7} \times(2.2)^{2}=3.7 \times 10^{-3} \mathrm{C}$
Asked in: JEE Mains - Electrostatics - Test 2