
A uniform thin metal plate of mass $10 \mathrm{~kg}$ with dimensions is shown. The ratio of $\mathrm{x}$ and…

Solution


$\begin{aligned} & \Rightarrow \mathrm{m}_1 \mathrm{x}_1+\mathrm{m}_2 \mathrm{x}_2=\mathrm{m}_3 \mathrm{x}_3 \\ & 10 \mathrm{x}_1+2(1.5)=12(1.5) \Rightarrow \mathrm{x}_1=1.5 \mathrm{~cm} \\ & \Rightarrow \mathrm{m}_1 \mathrm{y}_1+\mathrm{m}_2 \mathrm{y}_2=\mathrm{m}_3 \mathrm{y}_3 \\ & 10 \mathrm{y}_1+2(1.5)=12 \times 1 \Rightarrow \mathrm{y}_1=0.9 \mathrm{~cm} \\ & \frac{\mathrm{x}_1}{\mathrm{y}_1}=\frac{1.5}{0.9}=\frac{15}{9} \\ & \mathrm{n}=15\end{aligned}$
Asked in: JEE Main 2024 (08 Apr Shift 1)
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