A uniform string is vibrating with a fundamental frequency ' $n$ '. If radius and length of string both are…

A uniform string is vibrating with a fundamental frequency ' $n$ '. If radius and length of string both are doubled keeping tension constant then the new frequency of vibration is
  1. $2 \mathrm{n}$
  2. $3 \mathrm{n}$
  3. $\frac{n}{4}$
  4. $\frac{\mathrm{n}}{3}$

Solution

$\begin{aligned} & l_2=2 l_1, \mathrm{R}_2=2 \mathrm{R}_1, \mathrm{~T}_1=\mathrm{T}_2 \\ & \mathrm{n}=\frac{1}{2 l} \sqrt{\frac{\mathrm{T}}{\mathrm{m}}} \\ & \quad \text { Where, } \mathrm{m}=\text { mass per unit length }=\frac{\left(\mathrm{nR}^2 l\right) \rho}{l} \\ & \therefore \quad \mathrm{m} \propto \mathrm{R}^2 \\ & \therefore \quad \frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{l_1}{l_2} \times \frac{\mathrm{R}_1}{\mathrm{R}_2} \\ & \therefore \quad \frac{\mathrm{n}_2}{\mathrm{n}_1}=\frac{l_1}{2 l_1} \times \frac{\mathrm{R}_1}{2 \mathrm{R}_1} \\ & \therefore \quad \mathrm{n}_2=\frac{\mathrm{n}_1}{4}=\frac{\mathrm{n}}{4}\end{aligned}$

Asked in: MHT CET 2023 (12 May Shift 1)

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