A uniform rope of mass $0.1 \mathrm{~kg}$ and length $2.45 \mathrm{~m}$ hangs from a rigid support. The time…

A uniform rope of mass $0.1 \mathrm{~kg}$ and length $2.45 \mathrm{~m}$ hangs from a rigid support. The time taken by the transverse wave formed in the rope to travel through the full length of the rope is (Assume $g=9.8 \mathrm{~m} / \mathrm{s}^2$ )
  1. $0.5 \mathrm{~s}$
  2. $1.6 \mathrm{~s}$
  3. $1.2 \mathrm{~s}$
  4. $1.0 \mathrm{~s}$

Solution

The time taken by the transverse wave $t=2 \sqrt{\frac{l}{g}}=2 \sqrt{\frac{2.45}{9.8}}=1 \mathrm{~s}$

Asked in: AP EAMCET 2012

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