A uniform metal bar of length \(10 \mathrm{~m}\) with a crack at its midpoint is clamped between two rigid…

A uniform metal bar of length \(10 \mathrm{~m}\) with a crack at its midpoint is clamped between two rigid supports. The bar buckles upward due to temperature rise of \(40^{\circ} \mathrm{C}\). If the coefficient of linear expansion of the metal is \(2.5 \times 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\), the maximum displacement of the mid-point of the bar is
  1. \(11.3 \mathrm{~cm}\)
  2. \(22.3 \mathrm{~cm}\)
  3. \(33.3 \mathrm{~cm}\)
  4. \(44.3 \mathrm{~cm}\)

Solution

Given, length of bar \(L=10 \mathrm{~m}\), rise in temperature, \(\Delta T=40^{\circ} \mathrm{C}\) and coefficient of linear expansion, \(\alpha=25 \times 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\) As, linear expansion, \(\begin{aligned} \Delta L & =L \alpha \Delta t=10 \times 2.5 \times 10^{-6} \times 40 \\ \Rightarrow \Delta L & =0.1 \mathrm{~cm} \end{aligned}\) In the figure below, let the displacement of mid point of bar is \(x\),
Now, from \(\triangle O B A\), \(\begin{aligned} x & =\sqrt{(A B)^2-(O A)^2} \\ \Rightarrow x & =\sqrt{\left(\frac{10+0.001}{2}\right)^2-(5)^2} \\ \Rightarrow x & =0.223 \mathrm{~m} \end{aligned}\) \(\text{Hence, } x=22.3 \mathrm{~cm}\) Hence, the correct option is (b).

Asked in: AP EAMCET 2019 (23 Apr Shift 1)

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