A uniform chain of mass M and length L is lying on a smooth horizontal table, with half of its length…

A uniform chain of mass  M and length L is lying on a smooth horizontal table, with half of its length hanging down. The work done is pulling the entire chain up the table is
  1. M gL2
  2. MgL4
  3. MgL8
  4. MgL16

Solution

Work done is pulling the entire chain up the table = change in potential energy 

W=Uf-Ui

⇒W=0--M2gL4=MgL8

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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