A T.V. tower has a height of $100 \mathrm{~m}$. The average population density around the tower is $1000…

A T.V. tower has a height of $100 \mathrm{~m}$. The average population density around the tower is $1000 \mathrm{~km}^{-2}$ and radius of the earth is $6.37 \times 10^6 \mathrm{~m}$. The population covered is
  1. $4 \times 10^6$
  2. $6 \times 10^4$
  3. $16 \times 10^4$
  4. $8 \times 10^6$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

Practice more Communication System questions on Aicharya