A TV tower has a height \(160 \mathrm{~m}\). Its coverage range is nearly (Earth's radius, \(R_e=6400…
A TV tower has a height \(160 \mathrm{~m}\). Its coverage range is nearly (Earth's radius, \(R_e=6400 \mathrm{~km}\))
\(45255 \mathrm{~m}\)
\(55265 \mathrm{~m}\)
\(452.55 \mathrm{~km}\)
\(552.65 \mathrm{~m}\)
Solution
Given, height of a TV tower, \(h=160 \mathrm{~m}\)
Radius of earth, \(R=6400 \mathrm{~km}=6.4 \times 10^6 \mathrm{~m}\)
Coverage range of TV tower is given by
\(d=\sqrt{2 R h}=\sqrt{2 \times 6.4 \times 10^6 \times 160}=45254.8=45255 \mathrm{~m}\)