A transverse wave $y = 0.05 \sin (20\pi x - 50\pi t)$ in metre, is propagating along +ve $X$-axis on a string. A light insect starts crawling on the string with the velocity of $5 ext{ cms}^{-1}$ at $t = 0$ along the +ve $X$-axis from a point, where $x = 5 ext{ cm}$. After 5 s, the difference in…

Question

A transverse wave $y = 0.05 \sin (20\pi x - 50\pi t)$ in metre, is propagating along +ve $X$-axis on a string. A light insect starts crawling on the string with the velocity of $5	ext{ cms}^{-1}$ at $t = 0$ along the +ve $X$-axis from a point, where $x = 5	ext{ cm}$. After 5 s, the difference in the phase of its position is equal to

Aicharya · Accepted Answer

Phase difference, $\Delta\phi = \frac{2\pi}{\lambda} \cdot \Delta x = k (\Delta x) = k (v t)$ Here, $vt = 	ext{distance travelled by insect in given time interval.}$ or $\Delta\phi = (20\pi) (5 	imes 10^{-2} 	imes 5) = 5\pi$

A transverse wave $y = 0.05 \sin (20\pi x - 50\pi t)$ in metre, is propagating along +ve $X$-axis on a…

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