A transition element containing only one electron in $4 \mathrm{s}$ orbital is
- ${ }_{21} \mathrm{Sc}$
- ${ }_{23} \mathrm{Mn}$
- ${ }_{26} \mathrm{Fe}$
- ${ }_{29} \mathrm{Cu}$
Solution
$(3 \mathrm{d})^{10}(4 \mathrm{s})^{1}$ ~
Asked in: JEE-TOPICTESTS-CHEMISTRY
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