A transistor is operated in common-emitter configuration at $\mathrm{V}_{\mathrm{C}}=2 \mathrm{~V}$ such…

A transistor is operated in common-emitter configuration at $\mathrm{V}_{\mathrm{C}}=2 \mathrm{~V}$ such that a change in the base current from $100 \mu \mathrm{A}$ to $200 \mu \mathrm{A}$ produces a change in the collector current from $5 \mathrm{~mA}$ to $10 \mathrm{~mA}$. The current gain is :
  1. 50
  2. 75
  3. 100
  4. 150

Solution

$\begin{aligned} \Delta \mathrm{I}_{\mathrm{B}} & =100 \mu \mathrm{A} \\ \Delta \mathrm{I}_{\mathrm{C}} & =5 \mathrm{~mA} \\ \beta & =\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}=\frac{5 \times 10^{-3}}{100 \times 10^{-6}}=50 \end{aligned}$

Asked in: NEET 2009 (Mains)

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