A transistor is connected in common emitter configuration. The collector supply is 8   V and the…

A transistor is connected in common emitter configuration. The collector supply is 8 V and the voltage drop across a resistor of 800 Ω in the collector circuit is 0.5 V. If the current gain factor α is 0.96, the base current is
  1. 2.6×10−5A
  2. 3.6×10−5A
  3. 5.6×10−5A
  4. 6.6×10−5A

Solution

For a common emitter configuration, collector current is IC

IC=0.5800=0.625×10-3 A ; α=ICIE
Now, IB=IE-IC
IB=ICα-IC=IC1α-1

IB=26×10-6 A

Asked in: AP EAMCET 2021 (19 Aug Shift 1)

Practice more Semiconductors questions on Aicharya