A transformer operating at primary voltage 8 kV and secondary voltage 160   V serves a load of 80 &#160…

Since the transformer is assumed to be purely resistive, the power of the transformer can be calculated with $P=\frac{V^2}{R}$. Therefore,

For the primary coil,

$P=\frac{{\left(8\times {10}^3\right)}^2}{R_P}=80\times {10}^3 \mathrm{W}$

$\Rightarrow R_P=800 \mathrm{\Omega }$

For the secondary coil,

$P=\frac{{\left(160\right)}^2}{R_{\mathrm{S}}}=80\times {10}^3 \mathrm{W}$

$\Rightarrow R_S=0.32\mathrm{\Omega }$