A transformer has 20 turns in the primary and 100 turns in the secondary coil. An ac voltage of…
A transformer has 20 turns in the primary and 100 turns in the secondary coil. An ac voltage of $\mathrm{V}_{\text {in }}=600 \sin 314 \mathrm{t}$ is applied to primary terminal of transformer. Then maximum value of secondary output voltage obtained in volt is
600
300
3000
6000
Solution
We know,
$\frac{V_s}{V_p}=\frac{N_s}{N_p}$
$\therefore \quad$ The maximum value of secondary output voltage is:
$\begin{aligned}
V_s & =\frac{N_s}{N_p} \times V_p=\frac{100}{20} \times 600 \\
V_s & =3000 V
\end{aligned}$