A transformer has 120 turns in the primary coil and carries 5 A current. Input power is one kilowatt. To have 560 V output, the number of turns in secondary coil will be

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Aicharya · Accepted Answer

$\begin{aligned} 	herefore \quad & \frac{N_s}{N_p}=\frac{V_s}{V_p} \ & P=V I \ & \left.1000=V_p 	imes 5 \quad 	ext {...(given } P=1 \mathrm{~kW}, \mathrm{I}=5 \mathrm{~A}ight) \ \quad & \mathrm{V}_{\mathrm{p}}=\frac{1000}{5}=200 \mathrm{~V} \ 	herefore \quad & \frac{\mathrm{~N}_{\mathrm{s}}}{120}=\frac{560}{200} \ 	herefore \quad & \mathrm{~N}_{\mathrm{s}}=\frac{120 	imes 560}{200}=336\end{aligned}$

A transformer has 120 turns in the primary coil and carries 5 A current. Input power is one kilowatt. To…

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