A toroid has a core of inner radius $r_1$ and outer radius $r_2$, around which $N$ turns of wire are wound. If the current in the wire is $I$ then the magnetic field inside the toroid is ( $\mu_0=$ permeability of free space)

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Aicharya · Accepted Answer

Considering Ampearian loop at the centre of toroid: $\int \overrightarrow{B . d l}=\mu_0 N I$ Since, $B$ has radial symmetry $\&$ angle between $B \& d l$ is zero $\begin{aligned} & 	herefore B \int d l=B 2 \pi\left\{\frac{r_1+r_2}{2}ight\}=\mu_0 N I \ & \Rightarrow B=\left[\frac{\mu_0 N I}{\pi\left(r_1+r_2ight)}ight]\end{aligned}$

A toroid has a core of inner radius $r_1$ and outer radius $r_2$, around which $N$ turns of wire are wound.…

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