A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4 \pi imes 10^{-7}$ SI units):

Question

A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4 \pi 	imes 10^{-7}$ SI units):

Aicharya · Accepted Answer

The magnitude of magnetic field due to circular coil of $N$ turns is given by $\begin{aligned} & B_C=\frac{\mu_0 i N}{2 R} \ & =\frac{4 \pi 	imes 10^{-7} 	imes 7 	imes 100}{2 	imes 0.1} \ & =4.4 	imes 10^{-3} \mathrm{~T} \ & =4.4 \mathrm{mT} \end{aligned}$

A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic…

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