A thin uniform rod of length $\ell$ and mass $m$ is swinging freely about a horizontal axis passing through…

A thin uniform rod of length $\ell$ and mass $m$ is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is $\omega$. Its centre of mass rises to a maximum height of
  1. $\frac{1}{3} \frac{\ell^2 \omega^2}{g}$
  2. $\frac{1}{6} \frac{\ell \omega}{\mathrm{g}}$
  3. $\frac{1}{2} \frac{\ell^2 \omega^2}{g}$
  4. $\frac{1}{6} \frac{\ell^2 \omega^2}{\mathrm{~g}}$

Solution

$ \begin{aligned} & \text { } \\ & \text { T.E }=T . E_{\mathrm{f}} \\ & \frac{1}{2} I \omega^2=m g h \\ & \frac{1}{2} \times \frac{1}{3} m \ell^2 \omega^2=m g h \Rightarrow h=\frac{1}{6} \frac{\ell^2 \omega^2}{\mathrm{~g}} \end{aligned} $

Asked in: JEE Main 2009

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