A thin uniform bar of length $\mathrm{L}$ and mass $8 \mathrm{~m}$ lies on a smooth horizontal table. Two…

A thin uniform bar of length $\mathrm{L}$ and mass $8 \mathrm{~m}$ lies on a smooth horizontal table. Two point masses $\mathrm{m}$ and $2 \mathrm{~m}$ moving in the same horizontal plane from opposite sides of the bar with speeds $2 \mathrm{v}$ and $v$ respectively. The masses stick to the bar after collision at a distance $\frac{\mathrm{L}}{3}$ and $\frac{\mathrm{L}}{6}$ respectively from the centre of the bar. If the bar starts rotating about its center of mass as a result of collision, the angular speed of the bar will be:
  1. $\frac{\mathrm{v}}{6 \mathrm{~L}}$
  2. $\frac{6 \mathrm{v}}{5 \mathrm{~L}}$
  3. $\frac{3 \mathrm{v}}{5 \mathrm{~L}}$
  4. $\frac{\mathrm{v}}{5 \mathrm{~L}}$

Solution

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Asked in: JEE Main 2018 (15 Apr Shift 2 Online)

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