A thin transparent film with refractive index 1.4 , is held on circular ring of radius 1.8 cm. The fluid in…
Solution
When
$2 \mu x=n \lambda$
$\begin{aligned} \Rightarrow & \frac{d x}{d t}=\left(\frac{d n}{d t}\right) \frac{\lambda}{2 \mu} \\ & =\left(\frac{1}{12}\right) \frac{560 \times 10^{-9}}{2 \times 1.4}=\frac{5}{3} \times 10^{-8} \mathrm{~m} / \mathrm{s}\end{aligned}$
$\begin{aligned} & V=\text { Volume of film }=\pi R^2 x \\ & \frac{d V}{d t}=\pi R^2 \frac{d x}{d t} \\ & =\pi\left(1.8 \times 10^{-2}\right)^2 \frac{5}{3} \times 10^{-8} \mathrm{~m}^3 / \mathrm{s} \\ & =54 \pi \times 10^{-13} \mathrm{~m}^3 / \mathrm{s}\end{aligned}$
Asked in: JEE Main 2025 (28 Jan Shift 2)
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