A thin semicircular conducting ring P Q R of radius r is falling with its plane vertical in a horizontal magnetic field B , as shown in figure. The potential difference developed across the ring when its speed is v , is:

Question

Aicharya · Accepted Answer

Here we have to calculate the emf of the conducting ring when it is falling

So, we have to calculate with the following formulae

$e m f = V B l_{e q} = V B (2 R)$

where $R$ is at higher potential and $P$ is at lower potential.

A thin semicircular conducting ring P Q R of radius r is falling with its plane vertical in a horizontal…

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