A thin prism $\mathrm{P}_{1}$ with angle $4^{\circ}$ and made from glass of refractive index $1 \cdot 54$ is…

A thin prism $\mathrm{P}_{1}$ with angle $4^{\circ}$ and made from glass of refractive index $1 \cdot 54$ is combined with another thin prism $\mathrm{P}_{2}$ made from glass of refractive index $1 \cdot 72$ to produce dispersion without deviation. The angle of prism for $\mathrm{P}_{2}$ is
  1. $4^{\circ}$
  2. $5 \cdot 33^{\circ}$
  3. $2 \cdot 6^{\circ}$
  4. $3^{\circ}$

Solution

For thin prism the angle of deviation $\delta=\mathrm{A}(\mathrm{n}-1)$ $\therefore \delta_{1}=\delta_{2} \quad$ for no deviation $\therefore A_{1}\left(n_{1}-1\right)=A_{2}\left(n_{2}-1\right)$ $4(1.54-1)=\mathrm{A}_{2}(1.72-1)$ $\therefore 4 \times 0.54=\mathrm{A}_{2} \times 0.72$ $\mathrm{A}_{2}=\frac{4 \times 0.54}{0.72}=3^{\circ}$

Asked in: MHT CET 2020 (12 Oct Shift 1)

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