A thin prism of angle $15^{\circ}$ made of glass of refractive index $\mu_1=1.5$ is combined with another prism of glass of refractive index $\mu_2=1.75$. The combination of the prism produces dispersion without deviation. The angle of the second prism should be

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Aicharya · Accepted Answer

For without deviation $\begin{aligned} \frac{A}{A^{\prime}} & =\frac{\mu^{\prime}-1}{\mu-1} \ \frac{15^{\circ}}{A^{\prime}} & =\frac{1.75-1}{1.5-1} \ \frac{15}{A^{\prime}} & =\frac{0.75}{0.50} \ A^{\prime} & =\frac{0.50 	imes 15}{0.75}=10^{\circ} \end{aligned}$

A thin prism of angle $15^{\circ}$ made of glass of refractive index $\mu_1=1.5$ is combined with another…

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