A thin flexible wire of length $L$ is connected to two adjacent fixed points and carries a current $I$ in the clockwise direction, as shown in the figure. When the system is put in a uniform magnetic field of strength $B$ going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is

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Aicharya · Accepted Answer

$L=2 \pi R$ $R=\frac{L}{2 \pi}$ $2 T \sin (d \theta)=F_m$ for small angles, $\sin (d \theta) \approx d \theta$ $ \begin{aligned} \therefore \quad 2 T(d \theta) & =I(d L) B \sin 90^{\circ} \\ & =I(2 R \cdot d \theta) \cdot B \\ \therefore \quad T & =I R B=\frac{I L B}{2 \pi} \end{aligned} $ $\therefore$ correct option is (c)

A thin flexible wire of length $L$ is connected to two adjacent fixed points and carries a current $I$ in…

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