A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω . Two…

A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω. Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:
  1. ωMM+m
  2. ωM+2 mM
  3. ωMM+2 m
  4. ωM-2 mM+2 m

Solution

Using conservation of angular momentum
⇒Mr2ω=Mr2+2mr2ω'

⇒ω'=MωM+2 m.

Asked in: JEE Main 2021 (18 Mar Shift 1)

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